City F and City G is 576 km apart. Pierre left City F for City G at 10.00 a.m. travelling at an average speed of 72 km/h. Vaidev left City F later than Pierre and caught up with him at 1.00 p.m. Vaidev was travelling at a speed of 81 km/h.
- At what time did Vaidev leave City F?
- How much later did Pierre arrive in City G than Vaidev? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 1.00 p.m. = 3 h
Distance that Pierre covered when Vaidev caught up with Pierre
= 3 x 72
= 216 km
Time that Vaidev took to travel 216 km
= 216 ÷ 81
= 2
23 h
1 h = 60 min
23 h =
23 x 60 = 40 min
2
23 h = 2 h 40 min
Time that Vaidev left City F:
2 h 40 min before 1.00 p.m. = 10.20 a.m.
(b)
Remaining distance that they had to cover to reach City G
= 576 - 216
= 360 km
Duration that Vaidev had to travel before reaching City G
= 360 ÷ 81
= 4
49 h
Duration that Pierre had to travel before reaching City G
= 360 ÷ 72
= 5 h
Duration that Pierre took to arrive later than Vaidev in City G
= 5 - 4
49=
59 h
Answer(s): (a) 10.20 a.m.; (b)
59 h
