City V and City W is 540 km apart. Neave left City V for City W at 8.00 a.m. travelling at an average speed of 60 km/h. Albert left City V later than Neave and caught up with him at 12.00 p.m. Albert was travelling at a speed of 96 km/h.

1. At what time did Albert leave City V?
2. How much later did Neave arrive in City W than Albert? Express your answer in h as a fraction or mixed number.

(a)
From 8.00 a.m. to 12.00 p.m. = 4 h

Distance that Neave covered when Albert caught up with Neave
= 4 x 60
= 240 km

Time that Albert took to travel 240 km
= 240 ÷ 96
= 2¹₂ h

1 h = 60 min
¹₂ h = ¹₂ x 60 = 30 min
2¹₂ h = 2 h 30 min

Time that Albert left City V:
2 h 30 min before 12.00 p.m. = 9.30 a.m.

(b)
Remaining distance that they had to cover to reach City W
= 540 - 240
= 300 km

Duration that Albert had to travel before reaching City W
= 300 ÷ 96
= 3¹₈ h

Duration that Neave had to travel before reaching City W
= 300 ÷ 60
= 5 h

Duration that Neave took to arrive later than Albert in City W
= 5 - 3¹₈
= 1⁷₈ h

Answer(s): (a) 9.30 a.m.; (b) 1⁷₈ h