At 7 a.m., Jenson started from City P and travelled towards City Q and his speed remained constant throughout. At 8 a.m., Shiyun started her journey from City P towards City Q at an average speed of 66 km/h. Shiyun overtook Jenson at 1 p.m. After overtaking, Shiyun carried on her journey at the same average speed and reached at City Q at 1:20 p.m.
- Find Jenson's average speed in km/h.
- What is the distance between the two cities?
(a)
From 8 a.m. to 1 p.m. = 5 h
Distance that Shiyun had travelled until Shiyun overtook Jenson
= 5 x 66
= 330 km
From 7 a.m. to 1 p.m. = 6 h
Jenson's average speed
= 330 ÷ 6
= 55 km/h
(b)
From 8 a.m. to 1:20 p.m. = 5 h 20 min
1 h = 60 min
5 h 20 min = 5
20 60
h = 5
13 h
Distance between the two cities
= 5
13 x 66
=
163 x 66
= 352 km
Answer(s): (a) 55 km/h; (b) 352 km