At 8 a.m., Tom started from City L and travelled towards City M and his speed remained constant throughout. At 9 a.m., Gem started her journey from City L towards City M at an average speed of 80 km/h. Gem overtook Tom at 1 p.m. After overtaking, Gem carried on her journey at the same average speed and reached at City M at 4:15 p.m.
- Find Tom's average speed in km/h.
- What is the distance between the two cities?
(a)
From 9 a.m. to 1 p.m. = 4 h
Distance that Gem had travelled until Gem overtook Tom
= 4 x 80
= 320 km
From 8 a.m. to 1 p.m. = 5 h
Tom's average speed
= 320 ÷ 5
= 64 km/h
(b)
From 9 a.m. to 4:15 p.m. = 7 h 15 min
1 h = 60 min
7 h 15 min = 7
15 60
h = 7
14 h
Distance between the two cities
= 7
14 x 80
=
294 x 80
= 580 km
Answer(s): (a) 64 km/h; (b) 580 km