At 9 a.m., Bryan started from City U and travelled towards City V and his speed remained constant throughout. At 10 a.m., Fanny started her journey from City U towards City V at an average speed of 68 km/h. Fanny overtook Bryan at 1 p.m. After overtaking, Fanny carried on her journey at the same average speed and reached at City V at 4:15 p.m.
- Find Bryan's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 1 p.m. = 3 h
Distance that Fanny had travelled until Fanny overtook Bryan
= 3 x 68
= 204 km
From 9 a.m. to 1 p.m. = 4 h
Bryan's average speed
= 204 ÷ 4
= 51 km/h
(b)
From 10 a.m. to 4:15 p.m. = 6 h 15 min
1 h = 60 min
6 h 15 min = 6
15 60
h = 6
14 h
Distance between the two cities
= 6
14 x 68
=
254 x 68
= 425 km
Answer(s): (a) 51 km/h; (b) 425 km