At 9 a.m., Nick started from City Q and travelled towards City R and his speed remained constant throughout. At 10 a.m., Sabrina started her journey from City Q towards City R at an average speed of 70 km/h. Sabrina overtook Nick at 2 p.m. After overtaking, Sabrina carried on her journey at the same average speed and reached at City R at 3:30 p.m.
- Find Nick's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 2 p.m. = 4 h
Distance that Sabrina had travelled until Sabrina overtook Nick
= 4 x 70
= 280 km
From 9 a.m. to 2 p.m. = 5 h
Nick's average speed
= 280 ÷ 5
= 56 km/h
(b)
From 10 a.m. to 3:30 p.m. = 5 h 30 min
1 h = 60 min
5 h 30 min = 5
30 60
h = 5
12 h
Distance between the two cities
= 5
12 x 70
=
112 x 70
= 385 km
Answer(s): (a) 56 km/h; (b) 385 km