At 9 a.m., Cody started from City Z and travelled towards City A and his speed remained constant throughout. At 10 a.m., Abi started her journey from City Z towards City A at an average speed of 84 km/h. Abi overtook Cody at 3 p.m. After overtaking, Abi carried on her journey at the same average speed and reached at City A at 2:35 p.m.

1. Find Cody's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 3 p.m. = 5 h

Distance that Abi had travelled until Abi overtook Cody
= 5 x 84
= 420 km

From 9 a.m. to 3 p.m. = 6 h

Cody's average speed
= 420 ÷ 6
= 70 km/h

(b)
From 10 a.m. to 2:35 p.m. = 4 h 35 min

1 h = 60 min
4 h 35 min = 4 ³⁵ ₆₀
 h = 4 ⁷₁₂ h

Distance between the two cities
= 4 ⁷₁₂ x 84
= ⁵⁵₁₂ x 84
= 385 km

Answer(s): (a) 70 km/h; (b) 385 km