At 9 a.m., Albert started from City E and travelled towards City F and his speed remained constant throughout. At 10 a.m., Xuan started her journey from City E towards City F at an average speed of 75 km/h. Xuan overtook Albert at 2 p.m. After overtaking, Xuan carried on her journey at the same average speed and reached at City F at 4:20 p.m.
- Find Albert's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 2 p.m. = 4 h
Distance that Xuan had travelled until Xuan overtook Albert
= 4 x 75
= 300 km
From 9 a.m. to 2 p.m. = 5 h
Albert's average speed
= 300 ÷ 5
= 60 km/h
(b)
From 10 a.m. to 4:20 p.m. = 6 h 20 min
1 h = 60 min
6 h 20 min = 6
20 60
h = 6
13 h
Distance between the two cities
= 6
13 x 75
=
193 x 75
= 475 km
Answer(s): (a) 60 km/h; (b) 475 km