At 8 a.m., Gabriel started from City T and travelled towards City U and his speed remained constant throughout. At 10 a.m., Shiyun started her journey from City T towards City U at an average speed of 87 km/h. Shiyun overtook Gabriel at 2 p.m. After overtaking, Shiyun carried on her journey at the same average speed and reached at City U at 3:40 p.m.
- Find Gabriel's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 2 p.m. = 4 h
Distance that Shiyun had travelled until Shiyun overtook Gabriel
= 4 x 87
= 348 km
From 8 a.m. to 2 p.m. = 6 h
Gabriel's average speed
= 348 ÷ 6
= 58 km/h
(b)
From 10 a.m. to 3:40 p.m. = 5 h 40 min
1 h = 60 min
5 h 40 min = 5
40 60
h = 5
23 h
Distance between the two cities
= 5
23 x 87
=
173 x 87
= 493 km
Answer(s): (a) 58 km/h; (b) 493 km