At 8 a.m., George started from City X and travelled towards City Y and his speed remained constant throughout. At 9 a.m., Julie started her journey from City X towards City Y at an average speed of 66 km/h. Julie overtook George at 2 p.m. After overtaking, Julie carried on her journey at the same average speed and reached at City Y at 3:40 p.m.

1. Find George's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 9 a.m. to 2 p.m. = 5 h

Distance that Julie had travelled until Julie overtook George
= 5 x 66
= 330 km

From 8 a.m. to 2 p.m. = 6 h

George's average speed
= 330 ÷ 6
= 55 km/h

(b)
From 9 a.m. to 3:40 p.m. = 6 h 40 min

1 h = 60 min
6 h 40 min = 6 ⁴⁰ ₆₀
 h = 6 ²₃ h

Distance between the two cities
= 6 ²₃ x 66
= ²⁰₃ x 66
= 440 km

Answer(s): (a) 55 km/h; (b) 440 km