At 8 a.m., Zane started from City G and travelled towards City H and his speed remained constant throughout. At 10 a.m., Winnie started her journey from City G towards City H at an average speed of 78 km/h. Winnie overtook Zane at 2 p.m. After overtaking, Winnie carried on her journey at the same average speed and reached at City H at 3:40 p.m.

1. Find Zane's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 2 p.m. = 4 h

Distance that Winnie had travelled until Winnie overtook Zane
= 4 x 78
= 312 km

From 8 a.m. to 2 p.m. = 6 h

Zane's average speed
= 312 ÷ 6
= 52 km/h

(b)
From 10 a.m. to 3:40 p.m. = 5 h 40 min

1 h = 60 min
5 h 40 min = 5 ⁴⁰ ₆₀
 h = 5 ²₃ h

Distance between the two cities
= 5 ²₃ x 78
= ¹⁷₃ x 78
= 442 km

Answer(s): (a) 52 km/h; (b) 442 km