At 7 a.m., Howard started from City T and travelled towards City U and his speed remained constant throughout. At 10 a.m., Yoko started her journey from City T towards City U at an average speed of 72 km/h. Yoko overtook Howard at 1 p.m. After overtaking, Yoko carried on her journey at the same average speed and reached at City U at 3:20 p.m.

1. Find Howard's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 1 p.m. = 3 h

Distance that Yoko had travelled until Yoko overtook Howard
= 3 x 72
= 216 km

From 7 a.m. to 1 p.m. = 6 h

Howard's average speed
= 216 ÷ 6
= 36 km/h

(b)
From 10 a.m. to 3:20 p.m. = 5 h 20 min

1 h = 60 min
5 h 20 min = 5 ²⁰ ₆₀
 h = 5 ¹₃ h

Distance between the two cities
= 5 ¹₃ x 72
= ¹⁶₃ x 72
= 384 km

Answer(s): (a) 36 km/h; (b) 384 km