At 7 a.m., Neave started from City T and travelled towards City U and his speed remained constant throughout. At 10 a.m., Hilda started her journey from City T towards City U at an average speed of 78 km/h. Hilda overtook Neave at 1 p.m. After overtaking, Hilda carried on her journey at the same average speed and reached at City U at 4:30 p.m.

1. Find Neave's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 1 p.m. = 3 h

Distance that Hilda had travelled until Hilda overtook Neave
= 3 x 78
= 234 km

From 7 a.m. to 1 p.m. = 6 h

Neave's average speed
= 234 ÷ 6
= 39 km/h

(b)
From 10 a.m. to 4:30 p.m. = 6 h 30 min

1 h = 60 min
6 h 30 min = 6 ³⁰ ₆₀
 h = 6 ¹₂ h

Distance between the two cities
= 6 ¹₂ x 78
= ¹³₂ x 78
= 507 km

Answer(s): (a) 39 km/h; (b) 507 km