At 7 a.m., Bryan started from City K and travelled towards City L and his speed remained constant throughout. At 8 a.m., Jade started her journey from City K towards City L at an average speed of 84 km/h. Jade overtook Bryan at 1 p.m. After overtaking, Jade carried on her journey at the same average speed and reached at City L at 1:35 p.m.
- Find Bryan's average speed in km/h.
- What is the distance between the two cities?
(a)
From 8 a.m. to 1 p.m. = 5 h
Distance that Jade had travelled until Jade overtook Bryan
= 5 x 84
= 420 km
From 7 a.m. to 1 p.m. = 6 h
Bryan's average speed
= 420 ÷ 6
= 70 km/h
(b)
From 8 a.m. to 1:35 p.m. = 5 h 35 min
1 h = 60 min
5 h 35 min = 5
35 60
h = 5
712 h
Distance between the two cities
= 5
712 x 84
=
6712 x 84
= 469 km
Answer(s): (a) 70 km/h; (b) 469 km