At 7 a.m., Ken started from City V and travelled towards City W and his speed remained constant throughout. At 10 a.m., Pamela started her journey from City V towards City W at an average speed of 72 km/h. Pamela overtook Ken at 1 p.m. After overtaking, Pamela carried on her journey at the same average speed and reached at City W at 1:15 p.m.

1. Find Ken's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 1 p.m. = 3 h

Distance that Pamela had travelled until Pamela overtook Ken
= 3 x 72
= 216 km

From 7 a.m. to 1 p.m. = 6 h

Ken's average speed
= 216 ÷ 6
= 36 km/h

(b)
From 10 a.m. to 1:15 p.m. = 3 h 15 min

1 h = 60 min
3 h 15 min = 3 ¹⁵ ₆₀
 h = 3 ¹₄ h

Distance between the two cities
= 3 ¹₄ x 72
= ¹³₄ x 72
= 234 km

Answer(s): (a) 36 km/h; (b) 234 km