At 7 a.m., Ivan started from City H and travelled towards City J and his speed remained constant throughout. At 10 a.m., Irene started her journey from City H towards City J at an average speed of 66 km/h. Irene overtook Ivan at 1 p.m. After overtaking, Irene carried on her journey at the same average speed and reached at City J at 5:30 p.m.

1. Find Ivan's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 1 p.m. = 3 h

Distance that Irene had travelled until Irene overtook Ivan
= 3 x 66
= 198 km

From 7 a.m. to 1 p.m. = 6 h

Ivan's average speed
= 198 ÷ 6
= 33 km/h

(b)
From 10 a.m. to 5:30 p.m. = 7 h 30 min

1 h = 60 min
7 h 30 min = 7 ³⁰ ₆₀
 h = 7 ¹₂ h

Distance between the two cities
= 7 ¹₂ x 66
= ¹⁵₂ x 66
= 495 km

Answer(s): (a) 33 km/h; (b) 495 km