At 8 a.m., Wesley started from City U and travelled towards City V and his speed remained constant throughout. At 9 a.m., Hazel started her journey from City U towards City V at an average speed of 90 km/h. Hazel overtook Wesley at 2 p.m. After overtaking, Hazel carried on her journey at the same average speed and reached at City V at 3:50 p.m.
- Find Wesley's average speed in km/h.
- What is the distance between the two cities?
(a)
From 9 a.m. to 2 p.m. = 5 h
Distance that Hazel had travelled until Hazel overtook Wesley
= 5 x 90
= 450 km
From 8 a.m. to 2 p.m. = 6 h
Wesley's average speed
= 450 ÷ 6
= 75 km/h
(b)
From 9 a.m. to 3:50 p.m. = 6 h 50 min
1 h = 60 min
6 h 50 min = 6
50 60
h = 6
56 h
Distance between the two cities
= 6
56 x 90
=
416 x 90
= 615 km
Answer(s): (a) 75 km/h; (b) 615 km