At 8 a.m., Fabian started from City W and travelled towards City X and his speed remained constant throughout. At 10 a.m., Jade started her journey from City W towards City X at an average speed of 90 km/h. Jade overtook Fabian at 2 p.m. After overtaking, Jade carried on her journey at the same average speed and reached at City X at 4:20 p.m.
- Find Fabian's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 2 p.m. = 4 h
Distance that Jade had travelled until Jade overtook Fabian
= 4 x 90
= 360 km
From 8 a.m. to 2 p.m. = 6 h
Fabian's average speed
= 360 ÷ 6
= 60 km/h
(b)
From 10 a.m. to 4:20 p.m. = 6 h 20 min
1 h = 60 min
6 h 20 min = 6
20 60
h = 6
13 h
Distance between the two cities
= 6
13 x 90
=
193 x 90
= 570 km
Answer(s): (a) 60 km/h; (b) 570 km