At 8 a.m., Warren started from City F and travelled towards City G and his speed remained constant throughout. At 10 a.m., Tiffany started her journey from City F towards City G at an average speed of 66 km/h. Tiffany overtook Warren at 2 p.m. After overtaking, Tiffany carried on her journey at the same average speed and reached at City G at 4:30 p.m.

1. Find Warren's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 2 p.m. = 4 h

Distance that Tiffany had travelled until Tiffany overtook Warren
= 4 x 66
= 264 km

From 8 a.m. to 2 p.m. = 6 h

Warren's average speed
= 264 ÷ 6
= 44 km/h

(b)
From 10 a.m. to 4:30 p.m. = 6 h 30 min

1 h = 60 min
6 h 30 min = 6 ³⁰ ₆₀
 h = 6 ¹₂ h

Distance between the two cities
= 6 ¹₂ x 66
= ¹³₂ x 66
= 429 km

Answer(s): (a) 44 km/h; (b) 429 km