At 7 a.m., Bryan started from City P and travelled towards City Q and his speed remained constant throughout. At 9 a.m., Wendy started her journey from City P towards City Q at an average speed of 84 km/h. Wendy overtook Bryan at 1 p.m. After overtaking, Wendy carried on her journey at the same average speed and reached at City Q at 2:50 p.m.

1. Find Bryan's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 9 a.m. to 1 p.m. = 4 h

Distance that Wendy had travelled until Wendy overtook Bryan
= 4 x 84
= 336 km

From 7 a.m. to 1 p.m. = 6 h

Bryan's average speed
= 336 ÷ 6
= 56 km/h

(b)
From 9 a.m. to 2:50 p.m. = 5 h 50 min

1 h = 60 min
5 h 50 min = 5 ⁵⁰ ₆₀
 h = 5 ⁵₆ h

Distance between the two cities
= 5 ⁵₆ x 84
= ³⁵₆ x 84
= 490 km

Answer(s): (a) 56 km/h; (b) 490 km