At 8 a.m., Michael started from City X and travelled towards City Y and his speed remained constant throughout. At 9 a.m., Kylie started her journey from City X towards City Y at an average speed of 78 km/h. Kylie overtook Michael at 2 p.m. After overtaking, Kylie carried on her journey at the same average speed and reached at City Y at 5:20 p.m.

1. Find Michael's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 9 a.m. to 2 p.m. = 5 h

Distance that Kylie had travelled until Kylie overtook Michael
= 5 x 78
= 390 km

From 8 a.m. to 2 p.m. = 6 h

Michael's average speed
= 390 ÷ 6
= 65 km/h

(b)
From 9 a.m. to 5:20 p.m. = 8 h 20 min

1 h = 60 min
8 h 20 min = 8 ²⁰ ₆₀
 h = 8 ¹₃ h

Distance between the two cities
= 8 ¹₃ x 78
= ²⁵₃ x 78
= 650 km

Answer(s): (a) 65 km/h; (b) 650 km