At 8 a.m., Valen started from City A and travelled towards City B and his speed remained constant throughout. At 9 a.m., Kathy started her journey from City A towards City B at an average speed of 72 km/h. Kathy overtook Valen at 2 p.m. After overtaking, Kathy carried on her journey at the same average speed and reached at City B at 2:20 p.m.

1. Find Valen's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 9 a.m. to 2 p.m. = 5 h

Distance that Kathy had travelled until Kathy overtook Valen
= 5 x 72
= 360 km

From 8 a.m. to 2 p.m. = 6 h

Valen's average speed
= 360 ÷ 6
= 60 km/h

(b)
From 9 a.m. to 2:20 p.m. = 5 h 20 min

1 h = 60 min
5 h 20 min = 5 ²⁰ ₆₀
 h = 5 ¹₃ h

Distance between the two cities
= 5 ¹₃ x 72
= ¹⁶₃ x 72
= 384 km

Answer(s): (a) 60 km/h; (b) 384 km