At 7 a.m., Flynn started from City N and travelled towards City P and his speed remained constant throughout. At 9 a.m., Cathy started her journey from City N towards City P at an average speed of 78 km/h. Cathy overtook Flynn at 1 p.m. After overtaking, Cathy carried on her journey at the same average speed and reached at City P at 3:50 p.m.
- Find Flynn's average speed in km/h.
- What is the distance between the two cities?
(a)
From 9 a.m. to 1 p.m. = 4 h
Distance that Cathy had travelled until Cathy overtook Flynn
= 4 x 78
= 312 km
From 7 a.m. to 1 p.m. = 6 h
Flynn's average speed
= 312 ÷ 6
= 52 km/h
(b)
From 9 a.m. to 3:50 p.m. = 6 h 50 min
1 h = 60 min
6 h 50 min = 6
50 60
h = 6
56 h
Distance between the two cities
= 6
56 x 78
=
416 x 78
= 533 km
Answer(s): (a) 52 km/h; (b) 533 km