At 8 a.m., George started from City W and travelled towards City X and his speed remained constant throughout. At 10 a.m., Jean started her journey from City W towards City X at an average speed of 66 km/h. Jean overtook George at 2 p.m. After overtaking, Jean carried on her journey at the same average speed and reached at City X at 1:50 p.m.

1. Find George's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 2 p.m. = 4 h

Distance that Jean had travelled until Jean overtook George
= 4 x 66
= 264 km

From 8 a.m. to 2 p.m. = 6 h

George's average speed
= 264 ÷ 6
= 44 km/h

(b)
From 10 a.m. to 1:50 p.m. = 3 h 50 min

1 h = 60 min
3 h 50 min = 3 ⁵⁰ ₆₀
 h = 3 ⁵₆ h

Distance between the two cities
= 3 ⁵₆ x 66
= ²³₆ x 66
= 253 km

Answer(s): (a) 44 km/h; (b) 253 km