At 8 a.m., Eric started from City L and travelled towards City M and his speed remained constant throughout. At 10 a.m., Sarah started her journey from City L towards City M at an average speed of 72 km/h. Sarah overtook Eric at 2 p.m. After overtaking, Sarah carried on her journey at the same average speed and reached at City M at 6:45 p.m.
- Find Eric's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 2 p.m. = 4 h
Distance that Sarah had travelled until Sarah overtook Eric
= 4 x 72
= 288 km
From 8 a.m. to 2 p.m. = 6 h
Eric's average speed
= 288 ÷ 6
= 48 km/h
(b)
From 10 a.m. to 6:45 p.m. = 8 h 45 min
1 h = 60 min
8 h 45 min = 8
45 60
h = 8
34 h
Distance between the two cities
= 8
34 x 72
=
354 x 72
= 630 km
Answer(s): (a) 48 km/h; (b) 630 km