At 9 a.m., Reggie started from City Z and travelled towards City A and his speed remained constant throughout. At 10 a.m., Sabrina started her journey from City Z towards City A at an average speed of 88 km/h. Sabrina overtook Reggie at 1 p.m. After overtaking, Sabrina carried on her journey at the same average speed and reached at City A at 6:30 p.m.
- Find Reggie's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 1 p.m. = 3 h
Distance that Sabrina had travelled until Sabrina overtook Reggie
= 3 x 88
= 264 km
From 9 a.m. to 1 p.m. = 4 h
Reggie's average speed
= 264 ÷ 4
= 66 km/h
(b)
From 10 a.m. to 6:30 p.m. = 8 h 30 min
1 h = 60 min
8 h 30 min = 8
30 60
h = 8
12 h
Distance between the two cities
= 8
12 x 88
=
172 x 88
= 748 km
Answer(s): (a) 66 km/h; (b) 748 km