At 8 a.m., Warren started from City D and travelled towards City E and his speed remained constant throughout. At 10 a.m., Xandra started her journey from City D towards City E at an average speed of 87 km/h. Xandra overtook Warren at 2 p.m. After overtaking, Xandra carried on her journey at the same average speed and reached at City E at 4:40 p.m.
- Find Warren's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 2 p.m. = 4 h
Distance that Xandra had travelled until Xandra overtook Warren
= 4 x 87
= 348 km
From 8 a.m. to 2 p.m. = 6 h
Warren's average speed
= 348 ÷ 6
= 58 km/h
(b)
From 10 a.m. to 4:40 p.m. = 6 h 40 min
1 h = 60 min
6 h 40 min = 6
40 60
h = 6
23 h
Distance between the two cities
= 6
23 x 87
=
203 x 87
= 580 km
Answer(s): (a) 58 km/h; (b) 580 km