At 8 a.m., Tim started from City N and travelled towards City P and his speed remained constant throughout. At 10 a.m., Xylia started her journey from City N towards City P at an average speed of 90 km/h. Xylia overtook Tim at 1 p.m. After overtaking, Xylia carried on her journey at the same average speed and reached at City P at 3:40 p.m.

1. Find Tim's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 1 p.m. = 3 h

Distance that Xylia had travelled until Xylia overtook Tim
= 3 x 90
= 270 km

From 8 a.m. to 1 p.m. = 5 h

Tim's average speed
= 270 ÷ 5
= 54 km/h

(b)
From 10 a.m. to 3:40 p.m. = 5 h 40 min

1 h = 60 min
5 h 40 min = 5 ⁴⁰ ₆₀
 h = 5 ²₃ h

Distance between the two cities
= 5 ²₃ x 90
= ¹⁷₃ x 90
= 510 km

Answer(s): (a) 54 km/h; (b) 510 km