At 9 a.m., Cole started from City Z and travelled towards City A and his speed remained constant throughout. At 10 a.m., Hilda started her journey from City Z towards City A at an average speed of 90 km/h. Hilda overtook Cole at 3 p.m. After overtaking, Hilda carried on her journey at the same average speed and reached at City A at 5:50 p.m.
- Find Cole's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 3 p.m. = 5 h
Distance that Hilda had travelled until Hilda overtook Cole
= 5 x 90
= 450 km
From 9 a.m. to 3 p.m. = 6 h
Cole's average speed
= 450 ÷ 6
= 75 km/h
(b)
From 10 a.m. to 5:50 p.m. = 7 h 50 min
1 h = 60 min
7 h 50 min = 7
50 60
h = 7
56 h
Distance between the two cities
= 7
56 x 90
=
476 x 90
= 705 km
Answer(s): (a) 75 km/h; (b) 705 km