At 8 a.m., Wesley started from City G and travelled towards City H and his speed remained constant throughout. At 10 a.m., Julie started her journey from City G towards City H at an average speed of 72 km/h. Julie overtook Wesley at 2 p.m. After overtaking, Julie carried on her journey at the same average speed and reached at City H at 1:50 p.m.
- Find Wesley's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 2 p.m. = 4 h
Distance that Julie had travelled until Julie overtook Wesley
= 4 x 72
= 288 km
From 8 a.m. to 2 p.m. = 6 h
Wesley's average speed
= 288 ÷ 6
= 48 km/h
(b)
From 10 a.m. to 1:50 p.m. = 3 h 50 min
1 h = 60 min
3 h 50 min = 3
50 60
h = 3
56 h
Distance between the two cities
= 3
56 x 72
=
236 x 72
= 276 km
Answer(s): (a) 48 km/h; (b) 276 km