At 9 a.m., John started from City J and travelled towards City K and his speed remained constant throughout. At 10 a.m., Sarah started her journey from City J towards City K at an average speed of 88 km/h. Sarah overtook John at 1 p.m. After overtaking, Sarah carried on her journey at the same average speed and reached at City K at 2:30 p.m.

1. Find John's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 1 p.m. = 3 h

Distance that Sarah had travelled until Sarah overtook John
= 3 x 88
= 264 km

From 9 a.m. to 1 p.m. = 4 h

John's average speed
= 264 ÷ 4
= 66 km/h

(b)
From 10 a.m. to 2:30 p.m. = 4 h 30 min

1 h = 60 min
4 h 30 min = 4 ³⁰ ₆₀
 h = 4 ¹₂ h

Distance between the two cities
= 4 ¹₂ x 88
= ⁹₂ x 88
= 396 km

Answer(s): (a) 66 km/h; (b) 396 km