At 8 a.m., Wesley started from City S and travelled towards City T and his speed remained constant throughout. At 9 a.m., Kathy started her journey from City S towards City T at an average speed of 72 km/h. Kathy overtook Wesley at 2 p.m. After overtaking, Kathy carried on her journey at the same average speed and reached at City T at 1:45 p.m.
- Find Wesley's average speed in km/h.
- What is the distance between the two cities?
(a)
From 9 a.m. to 2 p.m. = 5 h
Distance that Kathy had travelled until Kathy overtook Wesley
= 5 x 72
= 360 km
From 8 a.m. to 2 p.m. = 6 h
Wesley's average speed
= 360 ÷ 6
= 60 km/h
(b)
From 9 a.m. to 1:45 p.m. = 4 h 45 min
1 h = 60 min
4 h 45 min = 4
45 60
h = 4
34 h
Distance between the two cities
= 4
34 x 72
=
194 x 72
= 342 km
Answer(s): (a) 60 km/h; (b) 342 km