At 7 a.m., Paul started from City K and travelled towards City L and his speed remained constant throughout. At 10 a.m., Kylie started her journey from City K towards City L at an average speed of 84 km/h. Kylie overtook Paul at 1 p.m. After overtaking, Kylie carried on her journey at the same average speed and reached at City L at 5:40 p.m.

1. Find Paul's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 1 p.m. = 3 h

Distance that Kylie had travelled until Kylie overtook Paul
= 3 x 84
= 252 km

From 7 a.m. to 1 p.m. = 6 h

Paul's average speed
= 252 ÷ 6
= 42 km/h

(b)
From 10 a.m. to 5:40 p.m. = 7 h 40 min

1 h = 60 min
7 h 40 min = 7 ⁴⁰ ₆₀
 h = 7 ²₃ h

Distance between the two cities
= 7 ²₃ x 84
= ²³₃ x 84
= 644 km

Answer(s): (a) 42 km/h; (b) 644 km