At 8 a.m., Nick started from City N and travelled towards City P and his speed remained constant throughout. At 9 a.m., Jane started her journey from City N towards City P at an average speed of 84 km/h. Jane overtook Nick at 2 p.m. After overtaking, Jane carried on her journey at the same average speed and reached at City P at 1:35 p.m.
- Find Nick's average speed in km/h.
- What is the distance between the two cities?
(a)
From 9 a.m. to 2 p.m. = 5 h
Distance that Jane had travelled until Jane overtook Nick
= 5 x 84
= 420 km
From 8 a.m. to 2 p.m. = 6 h
Nick's average speed
= 420 ÷ 6
= 70 km/h
(b)
From 9 a.m. to 1:35 p.m. = 4 h 35 min
1 h = 60 min
4 h 35 min = 4
35 60
h = 4
712 h
Distance between the two cities
= 4
712 x 84
=
5512 x 84
= 385 km
Answer(s): (a) 70 km/h; (b) 385 km