At 8 a.m., Simon started from City V and travelled towards City W and his speed remained constant throughout. At 9 a.m., Tiffany started her journey from City V towards City W at an average speed of 90 km/h. Tiffany overtook Simon at 2 p.m. After overtaking, Tiffany carried on her journey at the same average speed and reached at City W at 3:30 p.m.
- Find Simon's average speed in km/h.
- What is the distance between the two cities?
(a)
From 9 a.m. to 2 p.m. = 5 h
Distance that Tiffany had travelled until Tiffany overtook Simon
= 5 x 90
= 450 km
From 8 a.m. to 2 p.m. = 6 h
Simon's average speed
= 450 ÷ 6
= 75 km/h
(b)
From 9 a.m. to 3:30 p.m. = 6 h 30 min
1 h = 60 min
6 h 30 min = 6
30 60
h = 6
12 h
Distance between the two cities
= 6
12 x 90
=
132 x 90
= 585 km
Answer(s): (a) 75 km/h; (b) 585 km