At 8 a.m., Fabian started from City R and travelled towards City S and his speed remained constant throughout. At 10 a.m., Abi started her journey from City R towards City S at an average speed of 72 km/h. Abi overtook Fabian at 2 p.m. After overtaking, Abi carried on her journey at the same average speed and reached at City S at 4:45 p.m.
- Find Fabian's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 2 p.m. = 4 h
Distance that Abi had travelled until Abi overtook Fabian
= 4 x 72
= 288 km
From 8 a.m. to 2 p.m. = 6 h
Fabian's average speed
= 288 ÷ 6
= 48 km/h
(b)
From 10 a.m. to 4:45 p.m. = 6 h 45 min
1 h = 60 min
6 h 45 min = 6
45 60
h = 6
34 h
Distance between the two cities
= 6
34 x 72
=
274 x 72
= 486 km
Answer(s): (a) 48 km/h; (b) 486 km