At 8 a.m., Jenson started from City A and travelled towards City B and his speed remained constant throughout. At 10 a.m., Julie started her journey from City A towards City B at an average speed of 66 km/h. Julie overtook Jenson at 2 p.m. After overtaking, Julie carried on her journey at the same average speed and reached at City B at 4:40 p.m.

1. Find Jenson's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 2 p.m. = 4 h

Distance that Julie had travelled until Julie overtook Jenson
= 4 x 66
= 264 km

From 8 a.m. to 2 p.m. = 6 h

Jenson's average speed
= 264 ÷ 6
= 44 km/h

(b)
From 10 a.m. to 4:40 p.m. = 6 h 40 min

1 h = 60 min
6 h 40 min = 6 ⁴⁰ ₆₀
 h = 6 ²₃ h

Distance between the two cities
= 6 ²₃ x 66
= ²⁰₃ x 66
= 440 km

Answer(s): (a) 44 km/h; (b) 440 km