At 9 a.m., Vaidev started from City U and travelled towards City V and his speed remained constant throughout. At 10 a.m., Hilda started her journey from City U towards City V at an average speed of 90 km/h. Hilda overtook Vaidev at 3 p.m. After overtaking, Hilda carried on her journey at the same average speed and reached at City V at 4:30 p.m.
- Find Vaidev's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 3 p.m. = 5 h
Distance that Hilda had travelled until Hilda overtook Vaidev
= 5 x 90
= 450 km
From 9 a.m. to 3 p.m. = 6 h
Vaidev's average speed
= 450 ÷ 6
= 75 km/h
(b)
From 10 a.m. to 4:30 p.m. = 6 h 30 min
1 h = 60 min
6 h 30 min = 6
30 60
h = 6
12 h
Distance between the two cities
= 6
12 x 90
=
132 x 90
= 585 km
Answer(s): (a) 75 km/h; (b) 585 km