At 7 a.m., Asher started from City Z and travelled towards City A and his speed remained constant throughout. At 10 a.m., Cathy started her journey from City Z towards City A at an average speed of 84 km/h. Cathy overtook Asher at 1 p.m. After overtaking, Cathy carried on her journey at the same average speed and reached at City A at 3:40 p.m.

1. Find Asher's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 1 p.m. = 3 h

Distance that Cathy had travelled until Cathy overtook Asher
= 3 x 84
= 252 km

From 7 a.m. to 1 p.m. = 6 h

Asher's average speed
= 252 ÷ 6
= 42 km/h

(b)
From 10 a.m. to 3:40 p.m. = 5 h 40 min

1 h = 60 min
5 h 40 min = 5 ⁴⁰ ₆₀
 h = 5 ²₃ h

Distance between the two cities
= 5 ²₃ x 84
= ¹⁷₃ x 84
= 476 km

Answer(s): (a) 42 km/h; (b) 476 km