At 7 a.m., Pierre started from City F and travelled towards City G and his speed remained constant throughout. At 8 a.m., Jane started her journey from City F towards City G at an average speed of 72 km/h. Jane overtook Pierre at 1 p.m. After overtaking, Jane carried on her journey at the same average speed and reached at City G at 1:20 p.m.

1. Find Pierre's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 8 a.m. to 1 p.m. = 5 h

Distance that Jane had travelled until Jane overtook Pierre
= 5 x 72
= 360 km

From 7 a.m. to 1 p.m. = 6 h

Pierre's average speed
= 360 ÷ 6
= 60 km/h

(b)
From 8 a.m. to 1:20 p.m. = 5 h 20 min

1 h = 60 min
5 h 20 min = 5 ²⁰ ₆₀
 h = 5 ¹₃ h

Distance between the two cities
= 5 ¹₃ x 72
= ¹⁶₃ x 72
= 384 km

Answer(s): (a) 60 km/h; (b) 384 km