At 8 a.m., Peter started from City B and travelled towards City C and his speed remained constant throughout. At 9 a.m., Kylie started her journey from City B towards City C at an average speed of 78 km/h. Kylie overtook Peter at 2 p.m. After overtaking, Kylie carried on her journey at the same average speed and reached at City C at 3:50 p.m.

1. Find Peter's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 9 a.m. to 2 p.m. = 5 h

Distance that Kylie had travelled until Kylie overtook Peter
= 5 x 78
= 390 km

From 8 a.m. to 2 p.m. = 6 h

Peter's average speed
= 390 ÷ 6
= 65 km/h

(b)
From 9 a.m. to 3:50 p.m. = 6 h 50 min

1 h = 60 min
6 h 50 min = 6 ⁵⁰ ₆₀
 h = 6 ⁵₆ h

Distance between the two cities
= 6 ⁵₆ x 78
= ⁴¹₆ x 78
= 533 km

Answer(s): (a) 65 km/h; (b) 533 km