At 7 a.m., Jenson started from City P and travelled towards City Q and his speed remained constant throughout. At 10 a.m., Diana started her journey from City P towards City Q at an average speed of 66 km/h. Diana overtook Jenson at 1 p.m. After overtaking, Diana carried on her journey at the same average speed and reached at City Q at 5:50 p.m.
- Find Jenson's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 1 p.m. = 3 h
Distance that Diana had travelled until Diana overtook Jenson
= 3 x 66
= 198 km
From 7 a.m. to 1 p.m. = 6 h
Jenson's average speed
= 198 ÷ 6
= 33 km/h
(b)
From 10 a.m. to 5:50 p.m. = 7 h 50 min
1 h = 60 min
7 h 50 min = 7
50 60
h = 7
56 h
Distance between the two cities
= 7
56 x 66
=
476 x 66
= 517 km
Answer(s): (a) 33 km/h; (b) 517 km