At 7 a.m., Flynn started from City Q and travelled towards City R and his speed remained constant throughout. At 10 a.m., Min started her journey from City Q towards City R at an average speed of 88 km/h. Min overtook Flynn at 1 p.m. After overtaking, Min carried on her journey at the same average speed and reached at City R at 1:30 p.m.
- Find Flynn's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 1 p.m. = 3 h
Distance that Min had travelled until Min overtook Flynn
= 3 x 88
= 264 km
From 7 a.m. to 1 p.m. = 6 h
Flynn's average speed
= 264 ÷ 6
= 44 km/h
(b)
From 10 a.m. to 1:30 p.m. = 3 h 30 min
1 h = 60 min
3 h 30 min = 3
30 60
h = 3
12 h
Distance between the two cities
= 3
12 x 88
=
72 x 88
= 308 km
Answer(s): (a) 44 km/h; (b) 308 km