At 8 a.m., Nick started from City Q and travelled towards City R and his speed remained constant throughout. At 9 a.m., Penelope started her journey from City Q towards City R at an average speed of 90 km/h. Penelope overtook Nick at 2 p.m. After overtaking, Penelope carried on her journey at the same average speed and reached at City R at 1:50 p.m.
- Find Nick's average speed in km/h.
- What is the distance between the two cities?
(a)
From 9 a.m. to 2 p.m. = 5 h
Distance that Penelope had travelled until Penelope overtook Nick
= 5 x 90
= 450 km
From 8 a.m. to 2 p.m. = 6 h
Nick's average speed
= 450 ÷ 6
= 75 km/h
(b)
From 9 a.m. to 1:50 p.m. = 4 h 50 min
1 h = 60 min
4 h 50 min = 4
50 60
h = 4
56 h
Distance between the two cities
= 4
56 x 90
=
296 x 90
= 435 km
Answer(s): (a) 75 km/h; (b) 435 km