At 9 a.m., Peter started from City S and travelled towards City T and his speed remained constant throughout. At 10 a.m., Gabby started her journey from City S towards City T at an average speed of 72 km/h. Gabby overtook Peter at 3 p.m. After overtaking, Gabby carried on her journey at the same average speed and reached at City T at 2:15 p.m.

1. Find Peter's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 3 p.m. = 5 h

Distance that Gabby had travelled until Gabby overtook Peter
= 5 x 72
= 360 km

From 9 a.m. to 3 p.m. = 6 h

Peter's average speed
= 360 ÷ 6
= 60 km/h

(b)
From 10 a.m. to 2:15 p.m. = 4 h 15 min

1 h = 60 min
4 h 15 min = 4 ¹⁵ ₆₀
 h = 4 ¹₄ h

Distance between the two cities
= 4 ¹₄ x 72
= ¹⁷₄ x 72
= 306 km

Answer(s): (a) 60 km/h; (b) 306 km