At 7 a.m., Caden started from City T and travelled towards City U and his speed remained constant throughout. At 8 a.m., Zoe started her journey from City T towards City U at an average speed of 90 km/h. Zoe overtook Caden at 1 p.m. After overtaking, Zoe carried on her journey at the same average speed and reached at City U at 1:30 p.m.
- Find Caden's average speed in km/h.
- What is the distance between the two cities?
(a)
From 8 a.m. to 1 p.m. = 5 h
Distance that Zoe had travelled until Zoe overtook Caden
= 5 x 90
= 450 km
From 7 a.m. to 1 p.m. = 6 h
Caden's average speed
= 450 ÷ 6
= 75 km/h
(b)
From 8 a.m. to 1:30 p.m. = 5 h 30 min
1 h = 60 min
5 h 30 min = 5
30 60
h = 5
12 h
Distance between the two cities
= 5
12 x 90
=
112 x 90
= 495 km
Answer(s): (a) 75 km/h; (b) 495 km