At 9 a.m., Wesley started from City H and travelled towards City J and his speed remained constant throughout. At 10 a.m., Wendy started her journey from City H towards City J at an average speed of 80 km/h. Wendy overtook Wesley at 1 p.m. After overtaking, Wendy carried on her journey at the same average speed and reached at City J at 5:45 p.m.

1. Find Wesley's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 1 p.m. = 3 h

Distance that Wendy had travelled until Wendy overtook Wesley
= 3 x 80
= 240 km

From 9 a.m. to 1 p.m. = 4 h

Wesley's average speed
= 240 ÷ 4
= 60 km/h

(b)
From 10 a.m. to 5:45 p.m. = 7 h 45 min

1 h = 60 min
7 h 45 min = 7 ⁴⁵ ₆₀
 h = 7 ³₄ h

Distance between the two cities
= 7 ³₄ x 80
= ³¹₄ x 80
= 620 km

Answer(s): (a) 60 km/h; (b) 620 km