At 9 a.m., Henry started from City F and travelled towards City G and his speed remained constant throughout. At 10 a.m., Lynn started her journey from City F towards City G at an average speed of 76 km/h. Lynn overtook Henry at 1 p.m. After overtaking, Lynn carried on her journey at the same average speed and reached at City G at 4:30 p.m.

1. Find Henry's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 1 p.m. = 3 h

Distance that Lynn had travelled until Lynn overtook Henry
= 3 x 76
= 228 km

From 9 a.m. to 1 p.m. = 4 h

Henry's average speed
= 228 ÷ 4
= 57 km/h

(b)
From 10 a.m. to 4:30 p.m. = 6 h 30 min

1 h = 60 min
6 h 30 min = 6 ³⁰ ₆₀
 h = 6 ¹₂ h

Distance between the two cities
= 6 ¹₂ x 76
= ¹³₂ x 76
= 494 km

Answer(s): (a) 57 km/h; (b) 494 km