At 8 a.m., Zane started from City L and travelled towards City M and his speed remained constant throughout. At 10 a.m., Hazel started her journey from City L towards City M at an average speed of 66 km/h. Hazel overtook Zane at 2 p.m. After overtaking, Hazel carried on her journey at the same average speed and reached at City M at 1:30 p.m.
- Find Zane's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 2 p.m. = 4 h
Distance that Hazel had travelled until Hazel overtook Zane
= 4 x 66
= 264 km
From 8 a.m. to 2 p.m. = 6 h
Zane's average speed
= 264 ÷ 6
= 44 km/h
(b)
From 10 a.m. to 1:30 p.m. = 3 h 30 min
1 h = 60 min
3 h 30 min = 3
30 60
h = 3
12 h
Distance between the two cities
= 3
12 x 66
=
72 x 66
= 231 km
Answer(s): (a) 44 km/h; (b) 231 km