At 8 a.m., Oliver started from City U and travelled towards City V and his speed remained constant throughout. At 10 a.m., Tammy started her journey from City U towards City V at an average speed of 72 km/h. Tammy overtook Oliver at 2 p.m. After overtaking, Tammy carried on her journey at the same average speed and reached at City V at 2:40 p.m.

1. Find Oliver's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 2 p.m. = 4 h

Distance that Tammy had travelled until Tammy overtook Oliver
= 4 x 72
= 288 km

From 8 a.m. to 2 p.m. = 6 h

Oliver's average speed
= 288 ÷ 6
= 48 km/h

(b)
From 10 a.m. to 2:40 p.m. = 4 h 40 min

1 h = 60 min
4 h 40 min = 4 ⁴⁰ ₆₀
 h = 4 ²₃ h

Distance between the two cities
= 4 ²₃ x 72
= ¹⁴₃ x 72
= 336 km

Answer(s): (a) 48 km/h; (b) 336 km